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Q.The solution of dydx=(4x+y+1)2\dfrac{dy}{dx} = (4x + y + 1)^2 is

a
tan⁡−1(4x+y+1)=x+C\tan^{-1}(4x + y + 1) = x + C
b
tan⁡−1(4x+y+1)=2x+C\tan^{-1}(4x + y + 1) = 2x + C
c
tan⁡(4x+y+1)=x+C\tan(4x + y + 1) = x + C
d
tan⁡(4x+y+1)=2x+C\tan(4x + y + 1) = 2x + C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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