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Q.The solution of dydx+2y=e3x\dfrac{dy}{dx} + 2y = e^{3x} is

a
y=e3x5+Ce−2xy = \dfrac{e^{3x}}{5} + C e^{-2x}
b
y=e3x5+Ce2xy = \dfrac{e^{3x}}{5} + C e^{2x}
c
y=e3x+Ce−2xy = e^{3x} + C e^{-2x}
d
y=e3x3+Ce−2xy = \dfrac{e^{3x}}{3} + C e^{-2x}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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