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Q.The solution of $\dfrac{dy}{dx} = \dfrac{1 + y^2}{y^3}$ is

a

y + \dfrac{1}{y} = x + C

b

y - \dfrac{1}{y} = x + C

c

y^2 - \dfrac{1}{y^2} = x + C

d

y^2 + \dfrac{1}{y^2} = x + C

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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