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Q.The differential equation representing the family of curves y=ekxy = e^{kx} is

a
dydx=ky\dfrac{dy}{dx} = k y
b
d2ydx2=ky\dfrac{d^2 y}{dx^2} = k y
c
yd2ydx2=(dydx)2y \dfrac{d^2 y}{dx^2} = (\dfrac{dy}{dx})^2
d
ydydx=ky \dfrac{dy}{dx} = k

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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