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Q.The solution of the differential equation xdydx+y=x4x \dfrac{dy}{dx} + y = x^4 with y(1)=0y(1)=0 is

a
y=x4515xy = \dfrac{x^4}{5} - \dfrac{1}{5x}
b
y=x5515xy = \dfrac{x^5}{5} - \dfrac{1}{5x}
c
y=x45+15xy = \dfrac{x^4}{5} + \dfrac{1}{5x}
d
y=x55+15xy = \dfrac{x^5}{5} + \dfrac{1}{5x}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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