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Q.The solution of dydx=y+3x+1\dfrac{dy}{dx} = \dfrac{y + 3}{x + 1} is

a
y+3=C(x+1)y + 3 = C (x + 1)
b
y−3=C(x+1)y - 3 = C (x + 1)
c
log⁡∣y+3∣=x+1+C\log|y + 3| = x + 1 + C
d
log⁡∣y−3∣=x+1+C\log|y - 3| = x + 1 + C

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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