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Q.The solution of (x+y+1)dx+(x+y−1)dy=0\left( x + y + 1 \right) dx + \left( x + y - 1 \right) dy = 0 is

a
x+y+tan⁡−1(x+y)=Cx + y + \tan^{-1}(x + y) = C
b
x+y−tan⁡−1(x+y)=Cx + y - \tan^{-1}(x + y) = C
c
tan⁡−1(x+y)=C\tan^{-1}(x + y) = C
d
x+y=Cx + y = C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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