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Q.The solution of dydx+y=sin⁡x\dfrac{dy}{dx} + y = \sin x is

a
y=−cos⁡x+Ce−xy = -\cos x + C e^{-x}
b
y=cos⁡x+Ce−xy = \cos x + C e^{-x}
c
y=sin⁡x+Cexy = \sin x + C e^x
d
y=−sin⁡x+Ce−xy = -\sin x + C e^{-x}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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