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Q.The solution of dydx=ay+bcy+d\dfrac{dy}{dx} = \dfrac{ay + b}{cy + d} is

a
log⁡∣ay+b∣=x+C\log|ay + b| = x + C
b
cy+d=Ceax+bcy + d = C e^{ax + b}
c
tan⁡−1(ay+bcy+d)=x+C\tan^{-1}\left(\dfrac{ay + b}{cy + d}\right) = x + C
d
ay+b=C(cy+d)ay + b = C (cy + d)

Correct Answer: Option D

The correct solution involves applying the fundamental concept to derive the final value step by step...

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