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Q.The solution of dydx+y=xy2\dfrac{dy}{dx} + y = x y^2 is

a
1y=Cex2/21\dfrac{1}{y} = C e^{-x^2/2} - 1
b
1y=Cex2/2+1\dfrac{1}{y} = C e^{x^2/2} + 1
c
y=Cex2/2y = C e^{x^2/2}
d
1y=Cex2/2+1\dfrac{1}{y} = C e^{-x^2/2} + 1

Correct Answer: Option D

The correct solution involves applying the fundamental concept to derive the final value step by step...

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