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Q.The solution of dydx=1y2−4y−5\dfrac{dy}{dx} = \dfrac{1}{y^2 - 4y - 5} is

a
log⁡∣y−5∣−log⁡∣y+1∣=x+C\log|y-5| - \log|y+1| = x + C
b
log⁡∣y+5∣−log⁡∣y−1∣=x+C\log|y+5| - \log|y-1| = x + C
c
log⁡∣y−5∣+log⁡∣y+1∣=x+C\log|y-5| + \log|y+1| = x + C
d
log⁡∣y+5∣+log⁡∣y−1∣=x+C\log|y+5| + \log|y-1| = x + C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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