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Q.The drift velocity of electrons in a copper wire of cross-sectional area 11 mm² carrying a current of 11 A is (given n=8.5×1028n = 8.5 \times 10^{28} m⁻³, e=1.6×1019e = 1.6 \times 10^{-19} C)

a
7.4×1067.4 \times 10^{-6} m/s
b
1.18×1051.18 \times 10^{-5} m/s
c
3.7×1053.7 \times 10^{-5} m/s
d
1.18×1041.18 \times 10^{-4} m/s

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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