Q.A capacitor of capacitance $C$ is charged to potential difference $V_0$ . The plates are then connected to an ideal inductor of inductance $L$ . The maximum current in the circuit is (JEE Main 2023)

V_0 \sqrt{C/L}

V_0 \sqrt{L/C}

V_0 C/L

V_0 L/C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.A capacitor of capacitance CCC is charged to potential difference V0V_0V0​. The plates are then connected to an ideal inductor of inductance LLL. The maximum current in the circuit is (JEE Main 2023)