Home/Question #3016
PracticeMedium

Q.The solution of the differential equation dydx+ycotx=5excosx\dfrac{dy}{dx} + y \cot x = 5e^x \cos x is

a
ysinx=ex+Cy \sin x = e^x + C
b
ysinx=5ex+Cy \sin x = 5e^x + C
c
ycosx=5ex+Cy \cos x = 5e^x + C
d
ycscx=5ex+Cy \csc x = 5e^x + C

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here