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Q.The solution of $\dfrac{dy}{dx} = e^{x+y} + x e^y$ is

a

e^{-y} = e^{-x} + \dfrac{x^2}{2} + C

b

e^y = e^x + \dfrac{x^2}{2} + C

c

e^{-y} = e^{-x} - \dfrac{x^2}{2} + C

d

e^y = e^x - \dfrac{x^2}{2} + C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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