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Q.The solution of dydx=y+1x(x+1)\dfrac{dy}{dx} = \dfrac{y + 1}{x(x + 1)} is

a
y+1=Cx(x+1)y + 1 = C x(x + 1)
b
y=Cx(x+1)y = C x(x + 1)
c
y−1=Cx(x+1)y - 1 = C x(x + 1)
d
log⁡∣y+1∣=log⁡x+log⁡(x+1)+C\log|y + 1| = \log x + \log(x + 1) + C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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