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Q.The solution of dydx+y=sin⁡x+cos⁡x\dfrac{dy}{dx} + y = \sin x + \cos x is

a
y=sin⁡x−cos⁡x+Ce−xy = \sin x - \cos x + C e^{-x}
b
y=sin⁡x+cos⁡x+Ce−xy = \sin x + \cos x + C e^{-x}
c
y=sin⁡x−cos⁡x+Cexy = \sin x - \cos x + C e^{x}
d
y=sin⁡x+cos⁡x+Cexy = \sin x + \cos x + C e^{x}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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The solution of \dfrac{dy}{dx} + y = \sin x + \cos x is... | ParikshaNiti