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Q.The solution of dydx=1+y2xy(y2−1)\dfrac{dy}{dx} = \dfrac{1 + y^2}{xy(y^2 - 1)} is

a
log⁡∣y2−1∣=log⁡x+C\log |y^2 - 1| = \log x + C
b
tan⁡−1y=log⁡x+C\tan^{-1} y = \log x + C
c
log⁡∣y2−1∣=log⁡∣x∣+C\log |y^2 - 1| = \log |x| + C
d
y2−1=Cx2y^2 - 1 = C x^2

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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