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Q.The solution of dydx=ytan⁡x−2sin⁡x\dfrac{dy}{dx} = y \tan x - 2 \sin x with y(0)=0 is

a
y=2cos⁡xy = 2 \cos x
b
y=sin⁡xy = \sin x
c
y=2sin⁡xy = 2 \sin x
d
y=cos⁡xy = \cos x

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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