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Q.The solution of dydx=x+y+32(x+y+1)\dfrac{dy}{dx} = \dfrac{x + y + 3}{2(x + y + 1)} is

a
x+y+2=Cex+y+2x + y + 2 = C e^{x+y+2}
b
x+y+2=C(x+y+2)x + y + 2 = C (x + y + 2)
c
tan⁡−1(x+y+2)=x+C\tan^{-1}(x + y + 2) = x + C
d
x+y+2=Cx+y+2x + y + 2 = C \sqrt{x + y + 2}

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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