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Q.The solution of dydx+ytanx=secx\dfrac{dy}{dx} + y \tan x = \sec x is

a
ysecx=tanx+Cy \sec x = \tan x + C
b
ysecx=x+Cy \sec x = x + C
c
ycosx=tanx+Cy \cos x = \tan x + C
d
ysinx=x+Cy \sin x = x + C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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