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Q.The solution of dydx=(y+x−2)/(y−x−4)\dfrac{dy}{dx} = (y + x - 2)/(y - x - 4) is

a
y−x+3=Cey+x−6y - x + 3 = C e^{y+x-6}
b
y+x−6=Cey−x+2y + x - 6 = C e^{y-x+2}
c
tan⁡−1(y−x−62)=x+C\tan^{-1} \left( \dfrac{y - x - 6}{2} \right) = x + C
d
y−x−6=C(y+x−2)y - x - 6 = C (y + x - 2)

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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