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Q.A dielectric slab of dielectric constant K is inserted to fill half the space (parallel to plates) between the plates of a parallel plate capacitor. The capacitance becomes (NEET 2022)

a
KC0/(K+1)K C_0/(K+1)
b
C0(K+1)/2C_0 (K+1)/2
c
2KC0/(K+1)2 K C_0/(K+1)
d
KC0K C_0

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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