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Q.A capacitor of capacitance CC is charged to potential V0V_0. It is then connected to an uncharged capacitor of capacitance C/2C/2. The loss in energy is (JEE Main 2023)

a
13CV02\dfrac{1}{3} C V_0^2
b
16CV02\dfrac{1}{6} C V_0^2
c
14CV02\dfrac{1}{4} C V_0^2
d
12CV02\dfrac{1}{2} C V_0^2

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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