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Q.A parallel plate capacitor is charged to 6060 V. After disconnecting, a slab of K=4K=4 is inserted. The potential difference becomes (JEE Main 2023)

a
1515 V
b
2020 V
c
3030 V
d
1010 V

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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