Home/Question #34

PracticeMedium

Q.A cell of emf $E$ and internal resistance $r$ sends current $I_1$ when connected to resistance $R_1$ and $I_2$ to $R_2$ . Then $r$ is

a

\dfrac{E(I_1 R_1 - I_2 R_2)}{I_1 I_2}

b

\dfrac{I_1 R_1 - I_2 R_2}{I_2 - I_1}

c

\dfrac{I_1 R_1 - I_2 R_2}{I_1 - I_2}

d

\dfrac{E(I_2 - I_1)}{I_1 I_2}

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here