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Q.A charged oil drop remains stationary in an electric field of 6 × 10⁵ N/C. If e = 1.6 × 10⁻¹⁹ C, the charge on the drop is

a
1.6 × 10⁻¹⁹ C
b
3.2 × 10⁻¹⁹ C
c
4.8 × 10⁻¹⁹ C
d
6.4 × 10⁻¹⁹ C

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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