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JEE Main 2022Medium

Q.The equation of the line passing through (1,1)(1,1) and parallel to 2x3y+4=02x - 3y + 4 = 0 is

a
2x3y+1=02x - 3y + 1 = 0
b
2x3y1=02x - 3y - 1 = 0
c
3x2y+1=03x - 2y + 1 = 0
d
3x2y1=03x - 2y - 1 = 0

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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