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JEE Main 2011Medium

Q.The equation of the line through (1,2)(1,2) and perpendicular to the line 3x+4y7=03x + 4y - 7 = 0 is

a
4x3y+2=04x - 3y + 2 = 0
b
4x+3y10=04x + 3y - 10 = 0
c
3x4y+5=03x - 4y + 5 = 0
d
4x3y+10=04x - 3y + 10 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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