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JEE Main 2009Medium

Q.The distance of the point (1,1) from the line 2x+3y6=02x + 3y - 6 = 0 is

a
113\dfrac{1}{\sqrt{13}}
b
513\dfrac{5}{\sqrt{13}}
c
713\dfrac{7}{\sqrt{13}}
d
1113\dfrac{11}{\sqrt{13}}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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