Home/Question #3563
JEE Main 2005Medium

Q.The equation of the line passing through (1,3) and (h,k) such that the area of triangle formed with axes is 6 sq units is

a
x(k−3)+y(h−1)=hk−6x(k-3) + y(h-1) = h k - 6
b
x(k−3)−y(h−1)=hkx(k-3) - y(h-1) = h k
c
x(3−k)+y(1−h)=6x(3-k) + y(1-h) = 6
d
x(k−3)+y(h−1)=2(hk−6)x(k-3) + y(h-1) = 2(h k - 6)

Correct Answer: Option D

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here