Q.The point of intersection of the lines $\dfrac{x-1}{1} = \dfrac{y-2}{2} = \dfrac{z-3}{3}$ and $\dfrac{x-2}{2} = \dfrac{y-3}{3} = \dfrac{z-4}{4}$ is

(3,6,9)

(1,2,3)

(2,4,6)

(4,8,12)

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The point of intersection of the lines x−11=y−22=z−33\dfrac{x-1}{1} = \dfrac{y-2}{2} = \dfrac{z-3}{3}1x−1​=2y−2​=3z−3​ and x−22=y−33=z−44\dfrac{x-2}{2} = \dfrac{y-3}{3} = \dfrac{z-4}{4}2x−2​=3y−3​=4z−4​ is