Q.The equation of the plane containing the line $x + y - z - 4 = 0 = 2x - y + z$ and parallel to the line $\dfrac{x}{1} = \dfrac{y-1}{2} = \dfrac{z+1}{3}$ is

x + y + z - 2 = 0

x - y - z + 2 = 0

3x + 4y + 5z - 6 = 0

x + y - z + 2 = 0

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The equation of the plane containing the line x+y−z−4=0=2x−y+zx + y - z - 4 = 0 = 2x - y + zx+y−z−4=0=2x−y+z and parallel to the line x1=y−12=z+13\dfrac{x}{1} = \dfrac{y-1}{2} = \dfrac{z+1}{3}1x​=2y−1​=3z+1​ is