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Q.The equation of the chord of the circle x2+y24x=0x^2 + y^2 - 4x = 0 which is bisected at the point (3,1) is

a
6x+2y20=06x + 2y - 20 = 0
b
6x2y16=06x - 2y - 16 = 0
c
3x+y10=03x + y - 10 = 0
d
3xy8=03x - y - 8 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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