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JEE Main 2010Medium

Q.The number of common tangents to the circles x2+y2=4x^2 + y^2 = 4 and x2+y28x+12=0x^2 + y^2 - 8x + 12 = 0 is

a
0
b
1
c
2
d
3

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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The number of common tangents to the circles x^2 + y^2 = 4... | ParikshaNiti