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JEE Main 2009Medium

Q.The equation of the tangent to the circle x2+y2=5x^2 + y^2 = 5 at the point (-2,1) is

a
2x+y+5=02x + y + 5 = 0
b
2xy5=02x - y - 5 = 0
c
2x+y5=02x + y - 5 = 0
d
2xy+5=02x - y + 5 = 0

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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