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JEE Main 2003Medium

Q.The equation of the circle with centre (2,1) and radius 3 is

a
(x−2)2+(y−1)2=9(x-2)^2 + (y-1)^2 = 9
b
x2+y2−4x−2y−4=0x^2 + y^2 - 4x - 2y - 4 = 0
c
x2+y2−4x−2y+4=0x^2 + y^2 - 4x - 2y + 4 = 0
d
(x+2)2+(y+1)2=9(x+2)^2 + (y+1)^2 = 9

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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