Q.The lines $p(p^2 + 1)x - y + q = 0$ and $(p^2 + 1)^2 x + (p^2 + 1)y + 2q = 0$ are perpendicular to each other if

p q = 1

p = q

p = -q

p q = -1

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The lines p(p2+1)x−y+q=0p(p^2 + 1)x - y + q = 0p(p2+1)x−y+q=0 and (p2+1)2x+(p2+1)y+2q=0(p^2 + 1)^2 x + (p^2 + 1)y + 2q = 0(p2+1)2x+(p2+1)y+2q=0 are perpendicular to each other if