Home/Question #3631
JEE Advanced 2023Medium

Q.The pair of straight lines joining the origin to the points of intersection of the line y=mx+cy = mx + c with the circle x2+y2=a2x^2 + y^2 = a^2 is

a
x2+y2−mxy=0x^2 + y^2 - m x y = 0
b
(c2−a2)x2+2cmxy+c2y2=0(c^2 - a^2)x^2 + 2 c m x y + c^2 y^2 = 0
c
x2−m2y2=0x^2 - m^2 y^2 = 0
d
a2(x2+y2)=c2y2a^2 (x^2 + y^2) = c^2 y^2

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here