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JEE Main 2022Medium

Q.If the pair of lines ax2+2hxy+by2+2gx+2fy+c=0ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0 represent two parallel lines, then

a
h2=abh^2 = ab, af2=bg2af^2 = bg^2, c(a+b)=2fgc(a + b) = 2fg
b
h2=abh^2 = ab, bg2=af2bg^2 = af^2, c(a+b)+2fg=0c(a + b) + 2fg = 0
c
ab=h2ab = h^2, af2=bg2af^2 = bg^2, c(a+b)=2fgc(a + b) = 2fg
d
ab=h2ab = h^2, bg2=af2bg^2 = af^2, c(a+b)=2fgc(a + b) = 2fg

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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