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JEE Main 2015Medium

Q.The joint equation of the pair of lines through (1,0) and parallel to the pair x24xy+3y2=0x^2 - 4xy + 3y^2 = 0 is

a
x24xy+3y2+4x2y=0x^2 - 4xy + 3y^2 + 4x - 2y = 0
b
x24xy+3y24x+2y=0x^2 - 4xy + 3y^2 - 4x + 2y = 0
c
x24xy+3y2+2x4y=0x^2 - 4xy + 3y^2 + 2x - 4y = 0
d
x24xy+3y22x+4y=0x^2 - 4xy + 3y^2 - 2x + 4y = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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