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JEE Main 2012Medium

Q.The pair of lines represented by 3x2+2xy−y2=03x^2 + 2xy - y^2 = 0 are perpendicular to the pair

a
3x2+2xy+y2=03x^2 + 2xy + y^2 = 0
b
x2+2xy+3y2=0x^2 + 2xy + 3y^2 = 0
c
3x2−2xy+y2=03x^2 - 2xy + y^2 = 0
d
x2−2xy+3y2=0x^2 - 2xy + 3y^2 = 0

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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