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JEE Main 2025Medium

Q.The pair of lines x2+2xy−3y2+8x+14y−20=0x^2 + 2xy - 3y^2 + 8x + 14y - 20 = 0 can be represented as

a
(x+3y−4)(x−y+5)=0(x + 3y - 4)(x - y + 5) = 0
b
(x+y−4)(x+3y+5)=0(x + y - 4)(x + 3y + 5) = 0
c
(x−y−4)(x+3y+5)=0(x - y - 4)(x + 3y + 5) = 0
d
(x+y+4)(x+3y−5)=0(x + y + 4)(x + 3y - 5) = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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