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JEE Main 2023Medium

Q.The condition that the pair of lines lx2+2mxy+ny2=0lx^2 + 2mxy + ny^2 = 0 may be perpendicular to the pair l′x2+2m′xy+n′y2=0l'x^2 + 2m'xy + n'y^2 = 0 is

a
ll′+mm′+nn′=0ll' + mm' + nn' = 0
b
ll′+mm′+nn′=0l l' + m m' + n n' = 0
c
l+l′+m+m′+n+n′=0l + l' + m + m' + n + n' = 0
d
ll′−mm′+nn′=0l l' - m m' + n n' = 0

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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