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JEE Main 2022Medium

Q.The pair of lines joining the origin to the points of intersection of the curve x2+y2=4x^2 + y^2 = 4 with the line x+y=1x + y = 1 is

a
x2−2xy+y2=0x^2 - 2xy + y^2 = 0
b
x2+2xy+y2=0x^2 + 2xy + y^2 = 0
c
x2−xy+y2=0x^2 - xy + y^2 = 0
d
x2+xy+y2=0x^2 + xy + y^2 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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