Q.The pair of lines $x^2 - 2xy - 3y^2 = 0$ together with the pair $x^2 - 2xy + y^2 = 0$ form

rhombus

square

parallelogram

rectangle

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The pair of lines x2−2xy−3y2=0x^2 - 2xy - 3y^2 = 0x2−2xy−3y2=0 together with the pair x2−2xy+y2=0x^2 - 2xy + y^2 = 0x2−2xy+y2=0 form