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JEE Main 2024Medium

Q.The equation of the pair of lines through (2,3) and parallel to the pair x2+xy2y2=0x^2 + xy - 2y^2 = 0 is

a
x2+xy2y210x13y+30=0x^2 + xy - 2y^2 - 10x - 13y + 30 = 0
b
x2+xy2y2+10x+13y30=0x^2 + xy - 2y^2 + 10x + 13y - 30 = 0
c
x2xy+2y210x13y+30=0x^2 - xy + 2y^2 - 10x - 13y + 30 = 0
d
x2+xy2y210x+13y+30=0x^2 + xy - 2y^2 - 10x + 13y + 30 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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