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JEE Main 2011Medium

Q.The pair of lines x2+2xy+y2+2x+2y+1=0x^2 + 2xy + y^2 + 2x + 2y + 1 = 0 is

a
(x+y+1)2=0(x + y + 1)^2 = 0
b
(x+y−1)2=0(x + y - 1)^2 = 0
c
(x−y+1)2=0(x - y + 1)^2 = 0
d
(x−y−1)2=0(x - y - 1)^2 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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