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JEE Advanced 2024Medium

Q.The condition that the line lx+my+n=0lx + my + n = 0 may be a common tangent to the pair of lines ax2+2hxy+by2+2gx+2fy+c=0ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0 is

a
Δ=0\Delta = 0
b
c(l2a+2hlm+bm2)=(gl+fm+c)2c(l^2 a + 2 h l m + b m^2) = (g l + f m + c)^2
c
c(l2a+2hlm+bm2)=(gl+fm)2c(l^2 a + 2 h l m + b m^2) = (g l + f m)^2
d
n(l2a+2hlm+bm2)=(gl+fm)2n(l^2 a + 2 h l m + b m^2) = (g l + f m)^2

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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