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Q.The pair of lines x2−4xy+4y2−2x−4y+1=0x^2 - 4xy + 4y^2 - 2x - 4y + 1 = 0 is

a
(x−2y−1)2=0(x - 2y - 1)^2 = 0
b
(x−2y+1)2=0(x - 2y + 1)^2 = 0
c
(x+2y−1)2=0(x + 2y - 1)^2 = 0
d
(x+2y+1)2=0(x + 2y + 1)^2 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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